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string - PHP won't escape brackets if near variable in double quote

Hey everyone,

I'm having a bit of trouble understanding why PHP is not escaping brackets when they are near a variable in double quotes. I would really appreciate it if someone could help me out with this issue.

Here's an example of what I mean:

Let's say I have a variable called $num with a value of 5. If I try to echo something like "The value of $num is ($num)", I expect the output to be "The value of $num is (5)". However, PHP seems to ignore the brackets and outputs "The value of $num is $num".

I've tried using different escape characters, like backslashes before the brackets, but it doesn't seem to make a difference. Is there something I'm missing here? Is there a specific way to escape the brackets in this situation?

Any help or guidance would be greatly appreciated. Thanks in advance!

All Replies


Hey there,

I understand the frustration you are facing with PHP and its handling of brackets near variables in double quotes. I recently encountered a similar situation, and it took me a while to figure out a solution.

In PHP, when you use double quotes to define a string, PHP performs variable interpolation. This means that it tries to substitute the variable values into the string. However, when it encounters brackets within the string, it gets confused and doesn't handle them as expected.

To overcome this, I found that you can use the concatenation operator (dot) to concatenate the variable with the string instead of relying on variable interpolation. For example, you could write your echo statement like this: "The value of " . $num . " is (" . $num . ")".

By separating the string and variables, PHP won't get confused with the brackets anymore, and the output will be as desired - "The value of $num is (5)". It may require a little extra typing, but it does the trick.

I hope this helps you out, and let me know if you have any further questions!


Hey there,

I had encountered a similar issue in the past, and it can be a bit tricky to handle. When using double quotes in PHP, variables within the string are actually parsed and interpolated. However, if you want to include brackets near variables, you need to explicitly specify the variable name to avoid confusion.

In your case, where you want to have brackets around the $num variable, you can try using curly braces to enclose the variable name within the string. So the echo statement would look like this: "The value of {$num} is ({$num})".

By enclosing the variable name within curly braces, you ensure that PHP correctly recognizes the variable you intended while also allowing the brackets to be displayed as expected. This way, the output should be "The value of 5 is (5)".

Give it a try and let me know if it works for you!

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