php variables to array - opposite of "extract"

Hey there!

Yes, you can definitely convert your individual variables into an array in PHP. One way to achieve this is by manually creating an array and assigning each variable to a specific key.

In your case, you can use the following code to convert the variables into an array:

php
$name = "John";

$age = 30;

$city = "New York";



$person = array(

    "name" => $name,

    "age" => $age,

    "city" => $city

);

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Hey all,

I completely understand the need to convert individual variables into an array in PHP. It's actually a pretty common requirement in my experience. While manually creating an array is one approach, I'd like to share a different method that I find quite convenient.

In PHP, you can use the `compact()` function to convert variables into an associative array. This function takes variable names as arguments and creates an array where the variable names become the keys, and their respective values are assigned as values in the array.

Let me demonstrate with your example:

php
$name = "John";

$age = 30;

$city = "New York";



$person = compact('name', 'age', 'city');

php
$person = array(

    "name" => "John",

    "age" => 30,

    "city" => "New York"

);

Hey folks,

I've come across a similar situation where I needed to convert variables into an array in PHP, and I'd like to share my approach with you.

One way to accomplish this is by utilizing the `get_defined_vars()` function in PHP. This nifty function returns an array of all defined variables in the current scope, including their names as keys and their values. We can then extract the desired variables from this array and create a new one.

Here's an example:

php
$name = "John";

$age = 30;

$city = "New York";



$vars = get_defined_vars();

$person = array_intersect_key($vars, array_flip(['name', 'age', 'city']));

php
$person = array(

    "name" => "John",

    "age" => 30,

    "city" => "New York"

);

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