Hey everyone,
I'm currently working on a PHP project and I'm having a bit of difficulty with using a PHP variable inside the `src` attribute of an `img` tag.
I have a variable called `$imageName` which holds the name of an image file. In my HTML file, I want to dynamically display this image by using the value stored in the `$imageName` variable. Here's an example of what I'm trying to achieve:
```php
<?php
$imageName = "example.jpg";
?>
<img src="<?php echo $imageName; ?>" alt="Example Image">
```
However, when I inspect the rendered HTML in the browser, the `src` attribute is not being set to the value of the `$imageName` variable. Instead, it's just displaying the string `$imageName` itself.
I've tried a few different approaches, including using concatenation (`<img src="' . $imageName . '" alt="Example Image">`) and double quotes (`<img src="$imageName" alt="Example Image">`), but nothing seems to be working.
Am I missing something here? How can I properly use my PHP variable inside the `src` attribute of the `img` tag?
Any help or guidance would be greatly appreciated! Thanks in advance.
Hey,
I had a similar experience before, and it turned out that the issue was related to the file path of the image. Make sure that the image file you are trying to display is located in the correct directory relative to your PHP file.
Check if the image file is in the same directory or if it is in a subdirectory. In case it is in a subdirectory, you'll need to include the relative path to the image file in the `$imageName` variable.
For example, if your PHP file is in the root directory and the image is in a subdirectory called "images", you should set the `$imageName` variable like this:
Also, ensure that the file name and the case of the letters in the file name match exactly, as PHP file systems are often case-sensitive.
Give these suggestions a try and see if the image displays correctly in your HTML output. Let us know if you have any further questions or if the issue persists.