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Q:

PHP filesize() function (with example)

Hi everyone,

I hope you're all doing well. I have a question regarding the PHP `filesize()` function and I was hoping someone could help me out.

So, I'm currently working on a web application where users can upload files, and I need to be able to display the file size to them. After doing some research, I came across the `filesize()` function in PHP, but I'm not quite sure how to use it correctly.

I understand that the `filesize()` function returns the size of a file in bytes, but I'm unsure about the syntax and how to implement it in my code. It would be great if someone could provide me with a simple example of how to use this function.

Let's say I have a file called "example.txt" stored in the same directory as my PHP file. How would I use the `filesize()` function to retrieve the size of this file? Can I directly pass the file name as an argument to the function, or do I need to provide the file path as well?

I also have another scenario where the file is stored in a different directory. How would I modify the function to account for this?

Any help or guidance on the proper usage of the `filesize()` function would be greatly appreciated. Thank you in advance!

All Replies

bhagenes

Hey there,

I saw your question and I thought I could share my personal experience with using the `filesize()` function in PHP. I hope it helps!

To use the `filesize()` function, you just need to pass the file name or the file path and name as an argument. In your case, since the file "example.txt" is in the same directory as your PHP file, you can directly pass the file name to the function without including the file path.

Here's an example of how you could use the `filesize()` function to get the size of "example.txt":

php
$filename = "example.txt";
$filesize = filesize($filename);
echo "The size of $filename is " . $filesize . " bytes.";


The function will return the size of the file in bytes, which you can then store in a variable or directly display as shown in the example.

Now, let's consider the scenario where the file is stored in a different directory. In this case, you need to pass the complete file path along with the file name as the argument to the `filesize()` function.

Let's say the file "example.txt" is stored in a directory called "files". Here's an example of how you could modify the function to account for this:

php
$filepath = "files/example.txt";
$filesize = filesize($filepath);
echo "The size of $filepath is " . $filesize . " bytes.";


Make sure that the file path is correctly specified to ensure the function can locate the file.

I hope this helps you out! If you have any further questions, feel free to ask.

leora45

Hey everyone,

I came across this thread and couldn't resist sharing my personal experience with the `filesize()` function in PHP. It's been quite handy in my projects, so I thought I'd chime in!

Using the `filesize()` function is pretty straightforward. Just like the previous responses explained, you can pass either the file name or the file path and name as an argument to the function.

To give you an example from my own experience, let's say you have a file called "example.txt" located in a different directory, such as "uploads/files". In this case, you need to provide the complete file path to the function.

Here's how you can do it:

php
$filePath = "uploads/files/example.txt";
$fileSize = filesize($filePath);
echo "The size of $filePath is " . $fileSize . " bytes.";


Make sure to adjust the file path according to your project's structure. By doing so, the `filesize()` function will accurately return the size of the specified file in bytes.

If, on the other hand, your file is located in the same directory as your PHP file, you can simply pass the file name to the function directly, just like the previous responses provided. It's really convenient!

I hope this adds some value to the discussion and helps you out. If you have any further questions or need clarification, feel free to ask. Happy coding!

maudie.lemke

Hey there,

I stumbled upon this thread and noticed your question about using the `filesize()` function in PHP. I've had some experience with it, and I'd be happy to share my insights!

When it comes to the `filesize()` function, it's indeed used to retrieve the size of a file in bytes. However, there are a couple of things to keep in mind while working with it.

Firstly, to use the function, you need to provide either the file name or the file path and name as an argument. In the case of "example.txt" residing in the same directory as your PHP file, you can pass the file name itself to the `filesize()` function, just like the previous response explained.

Now, let's consider a scenario where the file is stored in a different directory. In such cases, you must ensure that the file path is correctly specified in order for the function to locate it accurately. If the file "example.txt" is stored in a directory called "files", you must include the complete file path when using the `filesize()` function.

Here's an example to illustrate this:

php
$filePath = "path/to/files/example.txt";
$fileSize = filesize($filePath);
echo "The size of $filePath is approximately " . $fileSize . " bytes.";


By providing the correct file path, you'll be able to retrieve the size of the file successfully.

Feel free to ask if you have any further questions or run into any issues. Good luck with your web application, and I hope this response is of help to you!

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