Fueling Your Coding Mojo

Buckle up, fellow PHP enthusiast! We're loading up the rocket fuel for your coding adventures...

Popular Searches:

How to use a sign plus in a PHP variable and get result?

Hey everyone,

I recently started learning PHP and I'm a bit confused about how to use a sign plus (+) in a PHP variable and get the desired result. I've tried searching online for an answer, but I haven't been able to find a clear explanation.

To give you some context, let's say I have a variable called $num1, which stores the value 5, and another variable called $num2, which stores the value 10. Now, I want to add these two variables together using the sign plus and store the result in a new variable called $sum.

I tried using the following code:

$sum = $num1 + $num2;

But when I echo the $sum variable, it just displays '15' instead of the expected sum of 5 and 10, which is 15. I'm not sure what I'm doing wrong here.

Could someone please explain how to properly use the plus sign in a PHP variable to achieve the desired result? Am I missing any important syntax or concept here?

Any help would be greatly appreciated. Thank you in advance!

All Replies


Hey everyone,

I had a similar issue when working with PHP and encountering the plus sign in variables. It can be perplexing at first, but I'm here to help!

In PHP, the plus sign (+) is primarily used for addition in numerical operations. However, there are cases where it can also be used for string concatenation.

Based on your code example, where $num1 stores 5 and $num2 stores 10, the expected result of adding them together should indeed be 15. So, the problem may not lie with the usage of the plus sign itself.

However, it's possible that either $num1 or $num2 is unknowingly being treated as a string. To confirm this, you can use the var_dump() function to check the variable types.

For example:


If you see the data type as 'string' instead of 'integer' for any of the variables, that might explain the unexpected result.

In such cases, you can try using the intval() function to explicitly convert the variables to integers before performing the addition. Here's an updated code snippet:

$num1 = intval($num1);
$num2 = intval($num2);
$sum = $num1 + $num2;

echo $sum; // The correct sum, 15, should now be displayed

By using the intval() function, we ensure that both variables are treated as integers before the addition operation. This should help you obtain the desired result.

Feel free to give it a try and let me know if it resolves your issue. If you have any further questions or need more assistance, don't hesitate to ask. Best of luck with your PHP coding endeavors!


Hey there,

I encountered a similar issue when I first started working with PHP. It's essential to understand that the plus sign (+) is used for arithmetic addition in PHP variables.

When you try to add two variables using the plus sign, make sure they contain numerical values. In your example, you mentioned that $num1 stores 5 and $num2 stores 10, so there shouldn't be any problem with the values. However, it's always a good practice to double-check the variable types.

Sometimes, issues can arise if the variables are actually stored as strings instead of integers. In such cases, PHP might perform string concatenation instead of addition.

To ensure that the variables are treated as integers, you can explicitly cast them to the integer type using the (int) keyword. Here's how you can modify your code to address this:

$num1 = (int) 5;
$num2 = (int) 10;
$sum = $num1 + $num2;

echo $sum; // This should now correctly display 15

By explicitly casting the variables as integers, we ensure that PHP interprets them as numerical values and performs the addition operation correctly. Give it a try and let me know if that solves your problem!

If you have any further queries or need more assistance, feel free to ask. Good luck with your PHP learning journey!

New to LearnPHP.org Community?

Join the community