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How do generators handle exceptions and errors within the generated values?

I'm an aspiring Python programmer who's been exploring the concept of generators. I recently wrote a program that generates a series of numbers using a generator, but I realized that I haven't considered what happens if an exception or error occurs while generating these values. I am curious to know how generators handle such situations.

Do generators automatically handle exceptions and errors that occur within the generated values, or is there something specific I need to do to handle them? I would appreciate it if someone could shed some light on this matter. Thank you!

All Replies


In my personal experience, generators in Python have proven to be efficient tools for handling exceptions and errors within generated values. When an exception occurs within a generator, it is raised just like in any other part of the code. However, the beauty of generators lies in their ability to resume execution after an exception is handled.

To elaborate further, consider a scenario where you have a generator function that reads data from a file line by line. If an error, such as an IOError, occurs while reading a line, the generator will raise the exception. You can catch this exception outside the generator using a try-except block and handle it according to your requirements.

Here's a simplified example to demonstrate this behavior:

def file_reader(file_path):
with open(file_path) as file:
for line in file:
yield line.strip()
except IOError:
print("Error occurred while reading the file.")

data_gen = file_reader("sample.txt")

for item in data_gen:

In this case, if an IOError occurs while reading a file, the generator will raise the exception, print the error message, and continue to the next line. This is advantageous because it allows you to handle errors gracefully without halting the execution of the entire program.

Remember, generators provide a flexible way to handle exceptions within the context of generating values. Utilize try-except blocks or any suitable error-handling mechanism to ensure smooth execution and proper handling of exceptions in your generator functions.


In my experience, generators in Python do handle exceptions and errors gracefully. When an exception occurs within a generator, the generator will raise the exception and can be caught using a try-except block outside the generator.

For example, let's say you have a generator function that generates a series of numbers, but encounters a ZeroDivisionError. The generator will raise the exception, and you can catch and handle it appropriately.

Here's a simple example to illustrate this:

def number_generator():
numbers = [1, 2, 3, 4, 5]
for num in numbers:
yield 10 / num
except ZeroDivisionError:
print("Oops! Division by zero occurred.")
yield 0

gen = number_generator()

for value in gen:

In this case, if the generator encounters a zero in the 'numbers' list, it will raise a ZeroDivisionError. However, we've added a try-except block to handle this scenario. When the exception occurs, the generator will print a message and yield 0 instead of raising the error. This way, the program continues executing without crashing.

So, be sure to handle exceptions and errors within your generator functions using try-except blocks or any other appropriate error-handling mechanism.

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