datetime - PHP Variable "must be of type DateTimeInterface, string given" error

User 1: Hey there!
I've faced a similar issue before. The error message you mentioned usually occurs when you're passing a string as an argument to a function that expects a DateTime object.

In your case, the issue lies in comparing the given date with the current date. The `$givenDate` variable is a string, not a DateTime object, which is why you're encountering the error. To fix this, you need to convert the string to a DateTime object.

Here's how you can do it:

php
$currentDate = new DateTime();

$givenDate = DateTime::createFromFormat('Y-m-d', '2021-05-20');



if ($givenDate < $currentDate) {

    echo "The given date has already passed.";

} else {

    echo "The given date is in the future.";

}

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User 2: Hi there,
I've encountered a similar issue with DateTime in PHP in the past. The error "must be of type DateTimeInterface, string given" suggests that you are passing a string where a DateTime object is expected.

In your code, the variable `$givenDate` is indeed a string, while the `<` operator expects both operands to be of type DateTime. To resolve this, you need to convert the string to a DateTime object using the DateTime constructor or the DateTime::createFromFormat method.

Here's an alternative approach using the constructor:

php
$currentDate = new DateTime();

$givenDate = new DateTime("2021-05-20");



if ($givenDate < $currentDate) {

    echo "The given date has already passed.";

} else {

    echo "The given date is in the future.";

}

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