Fueling Your Coding Mojo

Buckle up, fellow PHP enthusiast! We're loading up the rocket fuel for your coding adventures...

Popular Searches:

codeigniter - A PHP Error was encountered Severity: Notice Message: Undefined variable: result

I encountered an error while working with CodeIgniter and I'm not sure how to resolve it. The error message says "A PHP Error was encountered Severity: Notice Message: Undefined variable: result". I am working on a project that involves retrieving data from a database using CodeIgniter's query function. However, when I try to access the result of the query, I get this error.

I have already checked my code and made sure that the query is executed correctly and that the result variable is declared. I have also made sure that there are no typos or syntax errors in my code. Despite these efforts, I am still unable to resolve the issue.

Can anyone please help me understand what might be causing this error and how I can fix it? I would greatly appreciate any insights or suggestions. Thanks in advance!

All Replies


I've faced a similar issue in my CodeIgniter project before, where I encountered the "Undefined variable: result" error. This error is usually triggered when you try to access a variable that has not been defined or initialized.

To troubleshoot this, first double-check if you have properly declared the "result" variable. Ensure that it is initialized before trying to access it, and also ensure that it is in the correct scope. In CodeIgniter, it is common to assign query results to a variable using the "$this->db->query()" method, and then fetch the result using "$query->result()". So ensure that these steps are followed correctly.

Another thing to consider is the flow of your code. Make sure that the variable "result" is accessible in the specific context where you're trying to use it. Sometimes, if you're performing a conditional check or operating within a loop, the variable might not be accessible outside of those blocks. In such cases, you can try declaring the variable outside of those blocks, so it becomes accessible throughout your code.

Additionally, check for any naming conflicts or typos. Ensure that the variable name is consistent throughout your code, including any function or method calls. A small typo can lead to the "Undefined variable" notice.

If none of the above suggestions resolve your issue, sharing the relevant code snippet or the code surrounding the error would be helpful for the community to assist you further. They may be able to spot any specific issues or mistakes that you might have overlooked.

I hope this helps you in resolving the error. Feel free to ask if you have any more questions!


I have encountered a similar issue in the past while using CodeIgniter. The "Undefined variable: result" error typically occurs when the variable "result" is not defined or accessible at the point where it is being used. There are a few things you can check to resolve this error.

First, make sure that you have properly declared the variable "result" before trying to access it. Check if you have assigned the result of the query to this variable correctly. For example, if you are using the CodeIgniter query builder, you should assign the result to the variable using the "->result()" method.

Another aspect to consider is the scope of the variable. If you have declared the variable inside a function or loop, ensure that it is accessible outside of that specific context. If necessary, you can try declaring the variable outside of the function or loop to make it accessible throughout your code.

Furthermore, remember that CodeIgniter follows the Model-View-Controller (MVC) pattern, where the query execution and data retrieval usually happen in the model. Ensure that you have correctly initialized and loaded the model in the controller so that the query result can be assigned to the "result" variable.

If you have checked all these possibilities and the error still persists, it might be helpful to share the relevant parts of your code with the community. That way, other users can assist you in identifying any specific issues causing the error.

Hope this helps! Let me know if you need any further assistance.

New to LearnPHP.org Community?

Join the community